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y^2=0.49
We move all terms to the left:
y^2-(0.49)=0
We add all the numbers together, and all the variables
y^2-0.49=0
a = 1; b = 0; c = -0.49;
Δ = b2-4ac
Δ = 02-4·1·(-0.49)
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.96}}{2*1}=\frac{0-\sqrt{1.96}}{2} =-\frac{\sqrt{}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.96}}{2*1}=\frac{0+\sqrt{1.96}}{2} =\frac{\sqrt{}}{2} $
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